NEET Physics Thermodynamics Questions Solved


A sample of an ideal gas is taken through a cycle a shown in figure. It absorbs 50J of energy during the process AB, no heat during BC, rejects 70J during CA. 40J of work is done on the gas during BC. Internal energy of gas at A is 1500J, the internal energy at C would be

(1) 1590 J

(2) 1620 J

(3) 1540 J

(4) 1570 J

(1) ΔWAB=0 as V = constant

ΔQAB=ΔUAB=50J (Given)

UA=1500JUB=(1500+50)J=1550J

ΔWBC=ΔUBC=40J (Given)

ΔUBC=40J

UC=(1550+40)J=1590J

Difficulty Level:

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