# NEET Physics Thermodynamics Questions Solved

For an adiabatic expansion of a perfect gas, the value of $\frac{\Delta P}{P}$ is equal to

(1) $-\sqrt{\gamma }\frac{\Delta V}{V}$

(2) $-\frac{\Delta V}{V}$

(3) $-\gamma \frac{\Delta V}{V}$

(4) $-{\gamma }^{2}\frac{\Delta V}{V}$

(3) $P{V}^{\gamma }=$ constant : Differentiating both sides

$P\gamma {V}^{\gamma -1}dV+{V}^{\gamma }dP=0⇒\frac{dP}{P}=-\gamma \frac{dV}{V}$

Difficulty Level:

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