NEET Physics Thermodynamics Questions Solved


The volume of a gas is reduced adiabatically to 14 of its volume at 27°C, if the value of γ = 1.4, then the new temperature will be - 

(1) 350 × 40.4 K

(2) 300 × 40.4 K

(3) 150 × 40.4 K

(4) None of these

Concept Videos :-

#3 | Thermodynamic Processes
#4 | Isobaric Process
#5 | Isochoric & Isothermal Process
#6 | Interconversion of Graphs
#7 | Solved Example: 1
#8 | Solved Example: 2
#9 | Adiabatic Process
#10 | Solved Example: 3
#11 | Graphs in Adiabatic Process: 1
#12 | Graphs in Adiabatic Process: 2

Concept Questions :-

Types of processes

(2) For adiabatic change TVγ1 = constant

T2T1=V1V2γ1T2=V1V2γ1×T1

T2=VV/41.41×300=300×(4)0.4K

Difficulty Level:

  • 8%
  • 79%
  • 10%
  • 5%
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