# NEET Physics Thermodynamics Questions Solved

The pressure and density of a diatomic gas $\left(\gamma =7/5\right)$ change adiabatically from (P, d) to (P', d'). If $\frac{d\text{'}}{d}=32$, then $\frac{P\text{'}}{P}$ should be

(1) 1/128

(2) 32

(3) 128

(4) None of the above

(3) Volume of the gas $V=\frac{m}{d}$ and using $P{V}^{\gamma }$ = constant

We get $\frac{P\text{'}}{P}={\left(\frac{V}{V\text{'}}\right)}^{\gamma }= {\left(\frac{d\text{'}}{d}\right)}^{\gamma }={\left(32\right)}^{7/5}=128$

Difficulty Level:

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