# NEET Physics Thermodynamics Questions Solved

The latent heat of vaporisation of water is 2240 J/gm. If the work done in the process of expansion of 1 g is 168 J, then increase in internal energy is

(1) 2408 J

(2) 2240 J

(3) 2072 J

(4) 1904 J

(3) $\Delta Q=\Delta U+\Delta W$

$⇒\Delta U=\Delta Q-\Delta W=2240-168=2072\text{\hspace{0.17em}}J$

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