# NEET Physics Thermodynamics Questions Solved

For an isothermal expansion of a perfect gas, the value of $\frac{\Delta P}{P}$ is equal -

(1) $-{\gamma }^{1/2}\frac{\Delta V}{V}$

(2) $-\frac{\Delta V}{V}$

(3) $-\gamma \frac{\Delta V}{V}$

(4) $-{\gamma }^{2}\frac{\Delta V}{V}$

(2) Differentiate PV = constant w.r.t V

$P\Delta V+V\Delta P=0$$\frac{\Delta P}{P}=-\frac{\Delta V}{V}$

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