# NEET Physics Thermodynamics Questions Solved

In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas molecules absorb 30 J of heat and 10 J of work is done by the gas. If the initial internal energy of the gas was 40 J, then the final internal energy will be -

(1) 30 J

(2) 20 J

(3) 60 J

(4) 40 J

(3) $\Delta Q=\Delta U+\Delta W=\left({U}_{f}-{U}_{i}\right)+\Delta W$

$30=\left({U}_{f}-40\right)+10$${U}_{f}=60J$

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