# NEET Physics Thermodynamics Questions Solved

110 J of heat is added to a gaseous system, whose internal energy change is 40 J, then the amount of external work done is

(1) 150 J

(2) 70 J

(3) 110 J

(4) 40 J

(2) $\Delta Q=\Delta U+\Delta W$

$\Delta W=\Delta Q-\Delta U=100-40=70J$

Difficulty Level:

• 14%
• 77%
• 9%
• 2%