NEET Physics Thermodynamics Questions Solved


110 J of heat is added to a gaseous system, whose internal energy change is 40 J, then the amount of external work done is 

(1) 150 J

(2) 70 J

(3) 110 J

(4) 40 J

(2) ΔQ=ΔU+ΔW

ΔW=ΔQΔU=10040=70J

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