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Reaction that shows hydrogen as an oxidising agent is:

1. With iodine to give hydrogen iodide

2. With lithium to give lithium hydride

3. With nitrogen to give ammonia

4. With sulphur to give hydrogen sulphide

Subtopic:  Oxidizing & Reducing Agents |
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Fluorine is a strong oxidising agent because:

1. it has several isotopes

2. it is very small and has 7 electrons in valency shell

3. its valency is one

4. it is the first member of the halogen series

Subtopic:  Oxidizing & Reducing Agents |
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The oxidation state of Ni in Ni(CO)4 is:

1. zero

2. +4

3. +8 

4. +2

Subtopic:  Oxidizing & Reducing Agents |
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Sulphurous acid can be used as:

1. Oxidising agent

2. Reducing agent

3. Bleaching agent

4. All of the above

Subtopic:  Oxidizing & Reducing Agents |
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When SO2 is passed through acidified solution of potassium dichromate, then chromium sulphate is formed. The change in oxidation number of chromium is:

1. +4 to+2 

2. +5 to+3

3. +6 to+3

4. +7 to+2

Subtopic:  Oxidizing & Reducing Agents |
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In the reaction;

2Ag + 2H2SOAg2SO4 + 2H2O + SO2, H2SO4 acts as:

1. Oxidizing agent

2. Reducing agent

3. Dehydrating agent

4. None of the above

Subtopic:  Balancing of Equations |
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Which of the following shows the highest oxidation number in the combined state?

1. Os

2. Ru

3. Xe

4. All of the above

Subtopic:  Oxidizing & Reducing Agents |
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In the preparation of chlorine from HCl;  MnO2 acts as:

1. Reducing agent

2. Oxidising agent

3. Catalytic agent

4. Dehydrating agent

Subtopic:  Oxidizing & Reducing Agents |
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In the equation,

NO2- +  H2NO3- + 2H+ + ne-

n represents

1. 5

2. 1

3. 2

4. 3

Subtopic:  Oxidizing & Reducing Agents |
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Reaction between acidified K2Cr2O7 and iron (II) ions shown by the equation:

Cr2O72-(aq) + 6Fe2+(aq) +14H+(aq)2Cr3+(aq) + 7H2O(l) + 6Fe3+(aq)

The correct statement among the following is -

1. Colour of the solution changes from green to blue

2. Iron (II) ions are reduced 

3. Dichromate ions are reduced 

4. Hydrogen ions are reduced

Subtopic:  Oxidizing & Reducing Agents |
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