Fundamental frequency of an open pipe of length 0.5 m is equal to the frequency of the first overtone of a closed pipe of length l. The value of lc is (m

(1) 1.5

(2) 0.75

(3) 2

(4) 1

(2) First tone of open pipe = first overtone of closed pipe

$\frac{v}{2{l}_{0}}=\frac{3v}{4{l}_{c}}$${l}_{c}=\frac{3×2×0.5}{4}=0.75m$

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