If the velocity of sound in air is 350 m/s. Then the fundamental frequency of an open organ pipe of length 50 cm, will be

(1) 350 Hz

(2) 175 Hz

(3) 900 Hz

(4) 750 Hz

Concept Questions :-

Standing waves
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The fundamental note produced by a closed organ pipe is of frequency f. The fundamental note produced by an open organ pipe of same length will be of frequency

(1) $\frac{f}{2}$

(2) f

(3) 2f

(4) 4f

Concept Questions :-

Standing waves
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If the velocity of sound in air is 336 m/s. The maximum length of a closed pipe that would produce a just audible sound will be :

(1) 3.2 cm

(2) 4.2 m

(3) 4.2 cm

(4) 3.2 m

Concept Questions :-

Standing waves
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A cylindrical tube, open at both ends, has a fundamental frequency f0 in air. The tube is dipped vertically into water such that half of its length is inside water. The fundamental frequency of the air column now is

(1) 3 f0/4

(2) f0

(3) f0/2

(4) 2 f0

Concept Questions :-

Standing waves
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If the length of a closed organ pipe is 1.5 m and the velocity of sound is 330 m/s, then the frequency for the second note is

(1) 220 Hz

(2) 165 Hz

(3) 110 Hz

(4) 55 Hz

Concept Questions :-

Standing waves
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A pipe 30 cm long is open at both ends. Which harmonic mode of the pipe is resonantly excited by a 1.1 kHz source? (Take the speed of sound in air = 330 ms–1

(1) First

(2) Second

(3) Third

(4) Fourth

Concept Questions :-

Standing waves
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A source of sound placed at the open end of a resonance column sends an acoustic wave of pressure amplitude ${\rho }_{0}$ inside the tube. If the atmospheric pressure is ${\rho }_{A}$ , then the ratio of maximum and minimum pressure at the closed end of the tube will be :

1. $\frac{\left({\rho }_{A}+{\rho }_{0}\right)}{\left({\rho }_{A}-{\rho }_{0}\right)}$

2. $\frac{\left({\rho }_{A}+2{\rho }_{0}\right)}{\left({\rho }_{A}-2{\rho }_{0}\right)}$

3. $\frac{{\rho }_{A}}{{\rho }_{A}}$

4. $\frac{\left({\rho }_{A}+\frac{1}{2}{\rho }_{0}\right)}{\left({\rho }_{A}-\frac{1}{2}{\rho }_{0}\right)}$

Concept Questions :-

Standing waves
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two closed pipe produce 10 beats per second when emitting their fundamental nodes. If their length are in ratio of 25 : 26. Then their fundamental frequency in Hz, are :

(1) 270, 280

(2) 260, 270

(3) 260, 250

(4) 260, 280

Concept Questions :-

Standing waves
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If v is the speed of sound in the air then the shortest length of the closed pipe which resonates to a frequency n :

(1) $\frac{v}{4n}$

(2) $\frac{v}{2n}$

(3) $\frac{2n}{v}$

(4) $\frac{4n}{v}$

Concept Questions :-

Standing waves
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The frequency of fundamental tone in an open organ pipe of length 0.48 m is 320 Hz. The speed of sound is 320 m/sec. Frequency of fundamental tone in closed organ pipe will be :

(1) 153.8 Hz

(2) 160.0 Hz

(3) 320.0 Hz

(4) 143.2 Hz

Concept Questions :-

Standing waves