NEET Physics Semiconductor Electronics Questions Solved

The distance between the body centred atom and a corner atom in sodium (a = 4.225 Å) is
(a) 3.66 Å (b) 3.17 Å
(c) 2.99 Å (d) 2.54 Å

(a) Sodium has bcc structure. The distance between body centre and a corner = $\frac{\sqrt{3} a}{2}$

$\frac{\sqrt{3} \times 4.225}{2} = 3.66$ Å

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