For the given combination of gates, if the logic states of inputs A, B, C are as follows A = B = C = 0 and A = B = 1, C = 0 then the logic states of output D are

(a) 0, 0
(b) 0, 1
(c) 1, 0
(d) 1, 1

Concept Questions :-

Logic gates
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Difficulty Level:

Boolean algebra is essentially based on

(a) Truth                     (b) Logic
(c) Symbol                  (d) Numbers

Concept Questions :-

Logic gates

Difficulty Level:

The logic behind ‘NOR’ gate is that it gives

(a) High output when both the inputs are low

(b) Low output when both the inputs are low

(c) High output when both the inputs are high

(d) None of these

Concept Questions :-

Logic gates
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Difficulty Level:

A logic gate is an electronic circuit which

(a) Makes logic decisions

(b) Allows electrons flow only in one direction

(c) Works binary algebra

(d) Alternates between 0 and 1 values

Concept Questions :-

Logic gates

Difficulty Level:

A gate has the following truth table
P 1 1 0 0
Q 1 0 1 0
R 1 0 0 0

The gate is
(a) NOR                      (b) OR
(c) NAND                    (d) AND

Concept Questions :-

Logic gates
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Difficulty Level:

Which of the following gates will have an output of 1

Concept Questions :-

Logic gates
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Difficulty Level:

Which represents NAND gate

Concept Questions :-

Logic gates
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Difficulty Level:

What will be the input of A and B for the Boolean expression $\overline{\left(\mathrm{A}+\mathrm{B}\right)}·\left(\overline{\mathrm{A}·\mathrm{B}}\right)=1$
(a) 0, 0                            (b) 0, 1
(c) 1, 0                            (d) 1, 1

Concept Questions :-

Logic gates
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Difficulty Level:

If A and B are two inputs in AND gate, then AND gate has an output of 1 when the values of A and B are
(a) A = 0, B = 0                         (b) A = 1, B = 1
(c) A = 1, B = 0                         (d) A = 0, B = 1

Concept Questions :-

Logic gates
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Difficulty Level:

The Boolean equation of NOR gate is
(a) C = A + B               (b) $\mathrm{C}=\overline{\mathrm{A}+\mathrm{B}}$
(c) $C=A·B$                 (d) $\mathrm{C}=\overline{\mathrm{A}.\mathrm{B}}$

Concept Questions :-

Logic gates