In an experiment with sonometer a tuning fork of frequency 256 Hz resonates with a length of 25 cm and another tuning fork resonates with a length of 16 cm. Tension of the string remaining constant the frequency of the second tuning fork is

(1) 163.84 Hz

(2) 400 Hz

(3) 320 Hz

(4) 204.8 Hz

(2) In case of sonometer frequency is given by

$n=\frac{p}{2l}\sqrt{\frac{T}{m}}$$\frac{{n}_{2}}{{n}_{1}}=\frac{{l}_{1}}{{l}_{2}}⇒{n}_{2}=\frac{25}{16}×256=400\text{\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}}Hz$

Difficulty Level:

• 0%
• 70%
• 26%
• 6%