NEET Physics Semiconductor Electronics Questions Solved


The diode shown in the circuit is a silicon diode. The potential difference between the points A and B will be



(a) 6 V

(b) 0.6 V

(c) 0.7 V

(d) 0 V

(a) In the given condition diode is in reverse biasing so it acts as open circuit. Hence potential difference between A and B is 6V

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