The displacement of the interfering light waves are ${y}_{1}=4\mathrm{sin}\omega \text{\hspace{0.17em}}t$ and ${y}_{2}=3\mathrm{sin}\left(\omega \text{\hspace{0.17em}}t+\frac{\pi }{2}\right)$. What is the amplitude of the resultant wave :

(1) 5

(2) 7

(3) 1

(4) 0

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two waves are represented by ${y}_{1}=a\mathrm{sin}\left(\omega \text{\hspace{0.17em}}t+\frac{\pi }{6}\right)$ and ${y}_{2}=a\mathrm{cos}\omega \text{\hspace{0.17em}}t$. What will be their resultant amplitude :

(1) a

(2) $\sqrt{2}\text{\hspace{0.17em}}a$

(3) $\sqrt{3}\text{\hspace{0.17em}}a$

(4) 2a

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The amplitude of a wave represented by displacement equation $y=\frac{1}{\sqrt{a}}\mathrm{sin}\omega t±\frac{1}{\sqrt{b}}\mathrm{cos}\omega t$ will be

(1) $\frac{a+b}{ab}$

(2) $\frac{\sqrt{a}+\sqrt{b}}{ab}$

(3) $\frac{\sqrt{a}±\sqrt{b}}{ab}$

(4) $\sqrt{\frac{a+b}{ab}}$

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two tuning forks when sounded together produced 4 beats/sec. The frequency of one fork is 256. The number of beats heard increases when the fork of frequency 256 is loaded with wax. The frequency of the other fork is :

(1) 504

(2) 520

(3) 260

(4) 252

Concept Questions :-

Beats
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A tuning fork sounded together with a tuning fork of frequency 256 Hz emits two beats. On loading the tuning fork of frequency 256 Hz with wax, the number of beats heard are 1 per second. The frequency of the other tuning fork is :

(1) 257

(2) 258

(3) 256

(4) 254

Concept Questions :-

Beats
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If two tuning forks A and B are sounded together, they produce 4 beats per second. A is then slightly loaded with wax, they produce 2 beats when sounded again. The frequency of A is 256. The frequency of B will be :

(1) 250

(2) 252

(3) 260

(4) 262

Concept Questions :-

Beats
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two tuning forks have frequencies 450 Hz and 454 Hz respectively. On sounding these forks together, the time interval between successive maximum intensities will be :

(1) 1/4 sec

(2) 1/2 sec

(3) 1 sec

(4) 2 sec

Concept Questions :-

Beats
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork is :

(1) 334

(2) 339

(3) 343

(4) 347

Concept Questions :-

Beats
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Tuning fork F1 has a frequency of 256 Hz and it is observed to produce 6 beats/second with another tuning fork F2. When F2 is loaded with wax, it still produces 6 beats/second with F1. The frequency of F2 before loading was :

(1) 253 Hz

(2) 262 Hz

(3) 250 Hz

(4) 259 Hz

Concept Questions :-

Beats
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be :

(1) 502

(2) 507

(3) 517

(4) 522

Concept Questions :-

Beats