The displacement of a particle is given by $x=3\mathrm{sin}\left(5\pi \text{\hspace{0.17em}}t\right)+4\mathrm{cos}\left(5\pi \text{\hspace{0.17em}}t\right)$. The amplitude of the particle is :

(1) 3

(2) 4

(3) 5

(4) 7

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The two interfering waves have intensities in the ratio 9 : 4. The ratio of intensities of maxima and minima in the interference pattern will be :

(1) 1 : 25

(2) 25 : 1

(3) 9 : 4

(4) 4 : 9

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If the ratio of amplitude of two waves is 4 : 3. Then the ratio of maximum and minimum intensity will be :

(1) 16 : 18

(2) 18 : 16

(3) 49 : 1

(4) 1 : 49

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Equation of motion in the same direction is given by ${y}_{1}=A\mathrm{sin}\left(\omega t-kx\right)$, ${y}_{2}=A\mathrm{sin}\left(\omega t-kx-\theta \right)$. The amplitude of the medium particle will be

(1) $2A\mathrm{cos}\frac{\theta }{2}$

(2) $2A\mathrm{cos}\theta$

(3) $\sqrt{2}A\mathrm{cos}\frac{\theta }{2}$

(4) $1.2f,\text{\hspace{0.17em}}1.2\lambda$

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The displacement of the interfering light waves are ${y}_{1}=4\mathrm{sin}\omega \text{\hspace{0.17em}}t$ and ${y}_{2}=3\mathrm{sin}\left(\omega \text{\hspace{0.17em}}t+\frac{\pi }{2}\right)$. What is the amplitude of the resultant wave :

(1) 5

(2) 7

(3) 1

(4) 0

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two waves are represented by ${y}_{1}=a\mathrm{sin}\left(\omega \text{\hspace{0.17em}}t+\frac{\pi }{6}\right)$ and ${y}_{2}=a\mathrm{cos}\omega \text{\hspace{0.17em}}t$. What will be their resultant amplitude :

(1) a

(2) $\sqrt{2}\text{\hspace{0.17em}}a$

(3) $\sqrt{3}\text{\hspace{0.17em}}a$

(4) 2a

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The amplitude of a wave represented by displacement equation $y=\frac{1}{\sqrt{a}}\mathrm{sin}\omega t±\frac{1}{\sqrt{b}}\mathrm{cos}\omega t$ will be

(1) $\frac{a+b}{ab}$

(2) $\frac{\sqrt{a}+\sqrt{b}}{ab}$

(3) $\frac{\sqrt{a}±\sqrt{b}}{ab}$

(4) $\sqrt{\frac{a+b}{ab}}$

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two tuning forks when sounded together produced 4 beats/sec. The frequency of one fork is 256. The number of beats heard increases when the fork of frequency 256 is loaded with wax. The frequency of the other fork is :

(1) 504

(2) 520

(3) 260

(4) 252

Concept Questions :-

Beats
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A tuning fork sounded together with a tuning fork of frequency 256 Hz emits two beats. On loading the tuning fork of frequency 256 Hz with wax, the number of beats heard are 1 per second. The frequency of the other tuning fork is :

(1) 257

(2) 258

(3) 256

(4) 254

Concept Questions :-

Beats
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If two tuning forks A and B are sounded together, they produce 4 beats per second. A is then slightly loaded with wax, they produce 2 beats when sounded again. The frequency of A is 256. The frequency of B will be :

(1) 250

(2) 252

(3) 260

(4) 262

Concept Questions :-

Beats