Two sound waves (expressed in CGS units) given by ${y}_{1}=0.3\mathrm{sin}\frac{2\pi }{\lambda }\left(vt-x\right)$ and ${y}_{2}=0.4\mathrm{sin}\frac{2\pi }{\lambda }\left(vt-x+\theta \right)$ interfere. The resultant amplitude at a place where the phase difference is π/2 will be :

(1) 0.7 cm

(2) 0.1 cm

(3) 0.5 cm

(4) $\frac{1}{10}\sqrt{7}\text{\hspace{0.17em}}cm$

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If two waves having amplitudes 2A and A and same frequency and velocity, propagate in the same direction in the same phase, the resulting amplitude will be

(1) 3A

(2) $\sqrt{5}A$

(3) $\sqrt{2}A$

(4) A

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The intensity ratio of the two waves is 1 : 16. The ratio of their amplitudes is

(1) 1 : 16

(2) 1 : 4

(3) 4 : 1

(4) 2 : 1

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The superposing waves are represented by the following equations : ${y}_{1}=5\mathrm{sin}2\pi \left(10\text{\hspace{0.17em}}t-0.1x\right)$, ${y}_{2}=10\mathrm{sin}2\pi \left(20\text{\hspace{0.17em}}t-0.2x\right)$ Ratio of intensities $\frac{{I}_{\mathrm{max}}}{{I}_{\mathrm{min}}}$ will be :

(1) 1

(2) 9

(3) 4

(4) 16

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The displacement of a particle is given by $x=3\mathrm{sin}\left(5\pi \text{\hspace{0.17em}}t\right)+4\mathrm{cos}\left(5\pi \text{\hspace{0.17em}}t\right)$. The amplitude of the particle is :

(1) 3

(2) 4

(3) 5

(4) 7

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The two interfering waves have intensities in the ratio 9 : 4. The ratio of intensities of maxima and minima in the interference pattern will be :

(1) 1 : 25

(2) 25 : 1

(3) 9 : 4

(4) 4 : 9

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If the ratio of amplitude of two waves is 4 : 3. Then the ratio of maximum and minimum intensity will be :

(1) 16 : 18

(2) 18 : 16

(3) 49 : 1

(4) 1 : 49

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Equation of motion in the same direction is given by ${y}_{1}=A\mathrm{sin}\left(\omega t-kx\right)$, ${y}_{2}=A\mathrm{sin}\left(\omega t-kx-\theta \right)$. The amplitude of the medium particle will be

(1) $2A\mathrm{cos}\frac{\theta }{2}$

(2) $2A\mathrm{cos}\theta$

(3) $\sqrt{2}A\mathrm{cos}\frac{\theta }{2}$

(4) $1.2f,\text{\hspace{0.17em}}1.2\lambda$

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The displacement of the interfering light waves are ${y}_{1}=4\mathrm{sin}\omega \text{\hspace{0.17em}}t$ and ${y}_{2}=3\mathrm{sin}\left(\omega \text{\hspace{0.17em}}t+\frac{\pi }{2}\right)$. What is the amplitude of the resultant wave :

(1) 5

(2) 7

(3) 1

(4) 0

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two waves are represented by ${y}_{1}=a\mathrm{sin}\left(\omega \text{\hspace{0.17em}}t+\frac{\pi }{6}\right)$ and ${y}_{2}=a\mathrm{cos}\omega \text{\hspace{0.17em}}t$. What will be their resultant amplitude :

(1) a

(2) $\sqrt{2}\text{\hspace{0.17em}}a$

(3) $\sqrt{3}\text{\hspace{0.17em}}a$

(4) 2a

Concept Questions :-

Wave motion