# NEET Physics Waves Questions Solved

The phase difference between two waves represented by ${y}_{1}={10}^{-6}\mathrm{sin}\left[100\text{\hspace{0.17em}}t+\left(x/50\right)+0.5\right]m,$ ${y}_{2}={10}^{-6}\mathrm{cos}\text{\hspace{0.17em}}\left[100\text{\hspace{0.17em}}t+\left(x/50\right)\right]m$ where x is expressed in metres and t is expressed in seconds, is approximately