The phase difference between two waves represented by ${y}_{1}={10}^{-6}\mathrm{sin}\left[100\text{\hspace{0.17em}}t+\left(x/50\right)+0.5\right]m,$ ${y}_{2}={10}^{-6}\mathrm{cos}\text{\hspace{0.17em}}\left[100\text{\hspace{0.17em}}t+\left(x/50\right)\right]m$ where x is expressed in metres and t is expressed in seconds, is approximately:

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

A particle on the trough of a wave at any instant will come to the mean position after a time (T = time period)

(1) T/2

(2) T/4

(3) T

(4) 2T

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If the equation of the transverse wave is Y = 2sin(kx – 2t), then the maximum particle velocity is :

1. 4 units

2. 2 units

3. 0

4. 6 units

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

When two sound waves with a phase difference of π/2, and each having amplitude A and frequency ω, are superimposed on each other, then the maximum amplitude and frequency of the resultant wave is :

(1) $\frac{A}{\sqrt{2}}:\frac{\omega }{2}$

(2) $\frac{A}{\sqrt{2}}:\omega$

(3) $\sqrt{2}\text{\hspace{0.17em}}A:\frac{\omega }{2}$

(4) $\sqrt{2}\text{\hspace{0.17em}}A:\omega$

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is ‘a’ and the phase of A is ahead by π/3 than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter  is -

(1) 2a

(2) $a\sqrt{3}$

(3) $a\sqrt{2}$

(4) a

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The minimum intensity of sound is zero at a point due to two sources of nearly equal frequencies, when :

(1) Two sources are vibrating in opposite phase

(2) The amplitude of the two sources are equal

(3) At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line

(4) Both the sources are in the same phase

Concept Questions :-

Beats
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Two sound waves (expressed in CGS units) given by ${y}_{1}=0.3\mathrm{sin}\frac{2\pi }{\lambda }\left(vt-x\right)$ and ${y}_{2}=0.4\mathrm{sin}\frac{2\pi }{\lambda }\left(vt-x+\theta \right)$ interfere. The resultant amplitude at a place where the phase difference is π/2 will be :

(1) 0.7 cm

(2) 0.1 cm

(3) 0.5 cm

(4) $\frac{1}{10}\sqrt{7}\text{\hspace{0.17em}}cm$

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If two waves having amplitudes 2A and A and same frequency and velocity, propagate in the same direction in the same phase, the resulting amplitude will be

(1) 3A

(2) $\sqrt{5}A$

(3) $\sqrt{2}A$

(4) A

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The intensity ratio of the two waves is 1 : 16. The ratio of their amplitudes is

(1) 1 : 16

(2) 1 : 4

(3) 4 : 1

(4) 2 : 1

Concept Questions :-

Wave motion
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The superposing waves are represented by the following equations : ${y}_{1}=5\mathrm{sin}2\pi \left(10\text{\hspace{0.17em}}t-0.1x\right)$, ${y}_{2}=10\mathrm{sin}2\pi \left(20\text{\hspace{0.17em}}t-0.2x\right)$ Ratio of intensities $\frac{{I}_{\mathrm{max}}}{{I}_{\mathrm{min}}}$ will be :

(1) 1

(2) 9

(3) 4

(4) 16

Concept Questions :-

Wave motion