NEET Physics Waves Questions Solved

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Two waves are given by ${y}_{1}=a\mathrm{sin}\left(\omega t-kx\right)$ and ${y}_{2}=a\mathrm{cos}\left(\omega \text{\hspace{0.17em}}t-kx\right)$. The phase difference between the two waves is

(1) $\frac{\pi }{4}$

(2) π

(3) $\frac{\pi }{8}$

(4) $\frac{\pi }{2}$

(4) ${y}_{1}=a\mathrm{sin}\left(\omega t-kx\right)$

and ${y}_{2}=a\mathrm{cos}\left(\omega t-kx\right)=a\mathrm{sin}\text{\hspace{0.17em}}\left(\omega \text{\hspace{0.17em}}t-kx+\frac{\pi }{2}\right)$

Hence phase difference between these two is $\frac{\pi }{2}.$

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