# NEET Physics Wave Optics Questions Solved

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Direction of the first secondary maximum in the Fraunhofer diffraction pattern at a single slit is given by (a is the width of the slit)

(1) $a\mathrm{sin}\theta =\frac{\lambda }{2}$

(2) $a\mathrm{cos}\theta =\frac{3\lambda }{2}$

(3) $a\mathrm{sin}\theta =\lambda$

(4) $a\mathrm{sin}\theta =\frac{3\lambda }{2}$

(4) For nth secondary maxima path difference

$d\mathrm{sin}\theta =\left(2n+1\right)\frac{\lambda }{2}⇒a\mathrm{sin}\theta =\frac{3\lambda }{2}$

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