# NEET Physics Wave Optics Questions Solved

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In Young’s double slit experiment, distance between two sources is 0.1 mm. The distance of screen from the sources is 20 cm. Wavelength of light used is 5460 Å. Then angular position of the first dark fringe is

(1) 0.08°

(2) 0.16°

(3) 0.20°

(4) 0.313°

(4) Angular position of first dark fringe

$\theta =\frac{\lambda }{d}=\frac{5460×{10}^{-10}}{0.1×{10}^{-3}}×\frac{180}{\pi }$ (in degree)

= 0.313°

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