If two waves represented by ${y}_{1}=4\mathrm{sin}\omega t$ and ${y}_{2}=3\mathrm{sin}\left(\omega t+\frac{{\displaystyle \pi}}{{\displaystyle 3}}\right)$ interfere at a point, the amplitude of the resulting wave will be about

(1) 7

(2) 6

(3) 5

(4) 3.5

Concept Questions :-

Superposition principle

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two coherent sources of intensities, *I*_{1} and *I*_{2} produce an interference pattern. The maximum intensity in the interference pattern will be** **

(1) *I*_{1} + *I*_{2}

(2) ${I}_{1}^{2}+{I}_{2}^{2}$

(3) (*I*_{1} + *I*_{2})^{2}

(4) ${(\sqrt{{I}_{1}}+\sqrt{{I}_{2}})}^{2}$

Concept Questions :-

Superposition principle

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two beams of light having intensities *I* and 4*I* interfere to produce a fringe pattern on a screen. The phase difference between the beams is $\frac{\pi}{2}$ at point *A* and *π* at point *B*. Then the difference between the resultant intensities at *A* and *B* is

(1) 2*I*

(2) 4*I*

(3) 5*I*

(4) 7*I *

Concept Questions :-

Superposition principle

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two waves are represented by the equations ${y}_{1}=a\mathrm{sin}\omega t$ and ${y}_{2}=a\mathrm{cos}\omega t.$ The first wave** **

(1) Leads the second by *$\pi $*

(2) Lags the second by *$2\pi $*

(3) Leads the second by $\frac{\pi}{2}$

(4) Lags the second by $\frac{\pi}{2}$

Concept Questions :-

Superposition principle

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

If an interference pattern have maximum and minimum intensities in 36 : 1 ratio then what will be the ratio of amplitudes

(1) 5 : 7

(2) 7 : 4

(3) 4 : 7

(4) 7 : 5

Concept Questions :-

Superposition principle

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

In Young's double slit experiment, if the slit widths are in the ratio 1 : 9, then the ratio of the intensity at minima to that at maxima will be** **

(1) 1

(2) 1/9

(3) 1/4

(4) 1/3

Concept Questions :-

Young Double slit experiment

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

In a certain double slit experimental arrangement interference fringes of width 1.0 *mm* each are observed when light of wavelength 5000 Å is used. Keeping the set up unaltered, if the source is replaced by another source of wavelength 6000 Å, the fringe width will be** **

(1) 0.5 *mm*

(2) 1.0 *mm*

(3) 1.2 *mm*

(4) 1.5 *mm *

Concept Questions :-

Diffraction

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two coherent light sources *S*_{1} and *S*_{2} (λ= 6000 Å) are 1*mm* apart from each other. The screen is placed at a distance of 25 *cm* from the sources. The width of the fringes on the screen should be** **

(1) 0.015 *cm*

(2) 0.025 *cm*

(3) 0.010 *cm*

(4) 0.030 *cm *

Concept Questions :-

Diffraction

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The figure shows a double slit experiment *P* and *Q* are the slits. The path lengths *PX* and *QX* are *n*λ and (*n* + 2) λ respectively, where *n *is a whole number and *λ* is the wavelength. Taking the central fringe as zero, what is formed at *X*

(1) First bright

(2) First dark

(3) Second bright

(4) Second dark

Concept Questions :-

Young Double slit experiment

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The Young's experiment is performed with the lights of blue (λ = 4360 Å) and green colour (λ = 5460 Å), If the distance of the 4th fringe from the centre is *x*, then** **

(1) *x* (Blue) = *x* (Green)

(2) *x *(Blue)> *x* (Green)

(3) *x* (Blue) < *x* (Green)

(4) $\frac{x\left(Blue\right)}{x\left(Green\right)}=\frac{5460}{4360}$

Concept Questions :-

Young Double slit experiment

To view Explanation, Please buy any of the course from below.

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level: