The electric potential at a point (x, y) in the xy plane is given by V = –kxy. The field intensity at a distance r from the origin varies as

(1) r2

(2) r

(3) $\frac{1}{r}$

(4) $\frac{1}{{r}^{2}}$

Concept Videos :-

#7 | Relation b/w Electric Field&Potential 1
#8 | Relation b/w Electric Field&Potential 2

Concept Questions :-

Relation between field and potential

(2) ${E}_{x}=-\frac{dV}{dx}=-\text{\hspace{0.17em}}ky$; ${E}_{y}=-\frac{dV}{dy}=\text{\hspace{0.17em}}-kx$

$E=\sqrt{{E}_{x}^{2}+{E}_{y}^{2}}=k\sqrt{{x}^{2}+{y}^{2}}=kr$E r

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