Two capillary tubes P and Q are dipped in water. The height of water level in capillary P is 2/3 to the height in Q capillary. The ratio of their diameters is

(a) 2 : 3                           (b) 3 : 2
(c) 3 : 4                           (d) 4 : 3

(b) $\mathrm{r}\propto \frac{1}{\mathrm{h}}⇒\frac{{\mathrm{r}}_{\mathrm{p}}}{{\mathrm{r}}_{\mathrm{Q}}}=\frac{{\mathrm{h}}_{\mathrm{Q}}}{{\mathrm{h}}_{\mathrm{P}}}=\frac{\mathrm{h}}{\frac{2}{3}\mathrm{h}}=\frac{3}{2}$

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