The radii of two soap bubbles are ${\mathrm{r}}_{1}$ and ${\mathrm{r}}_{2}$ . In isothermal conditions, two meet together in vaccum. Then the radius of the resultant bubble is given by

(a) $\mathrm{R}=\left({\mathrm{r}}_{1}+{\mathrm{r}}_{2}\right)/2$                    (b) $\mathrm{R}={\mathrm{r}}_{1}\left({\mathrm{r}}_{1}{\mathrm{r}}_{2}+{\mathrm{r}}_{2}\right)$

(c) ${\mathrm{R}}^{2}={\mathrm{r}}_{1}^{2}+{\mathrm{r}}_{2}^{2}$                         (d) $\mathrm{R}={\mathrm{r}}_{1}+{\mathrm{r}}_{2}$

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