NEET Physics Mechanical Properties of Fluids Questions Solved


Two bodies are in equilibrium when suspended in water from the arms of a balance. The mass of one body is 36 g and its density is 9 g / cm3. If the mass of the other is 48 g, its density in g / cm3 is 
(a)43                                         (b) 32
(c) 3                                           (d) 5

(c) Apparent weight = V(ρ-σ)g=mρ(ρ-σ)g
where m = mass of the body,
ρ = density of the body
σ = density of water
If two bodies are in equilibrium then their apparent weight must be equal.

m1ρ1(ρ1-σ)=m2ρ2(ρ2-σ)369(9-1)=48ρ2(ρ2-1)

By solving we get ρ2=3.

Difficulty Level:

  • 22%
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  • 8%
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