The period of a simple pendulum measured inside a stationary lift is found to be T. If the lift starts accelerating upwards with acceleration of g/3 then the time period of the pendulum is

(a) T3

(b) T3

(c) 32T

(d) 3T

(c) For stationary lift T1=2πlg 

For ascending lift with acceleration a,

T2=2πlg+aT1T2=g+agTT2=g+g3g=43T2=32T

 

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