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The length of a wire is 1.0 m and the area of cross-section is $1.0×{10}^{-2}c{m}^{2}$. If the work done for increase in length by 0.2 cm is 0.4 joule, then Young's modulus of the material of the wire is

(a) $2.0×{10}^{10}N/{m}^{2}$             (b) $4×{10}^{10}N/{m}^{2}$

(c) $2.0×{10}^{11}N/{m}^{2}$             (d) $2×{10}^{10}N/{m}^{2}$