A particle moves in a straight line with a constant acceleration. It changes its velocity from 10 to  while passing through  a distance 135 m in t second . The value of t is

(a) 10

(b) 1.8

(c) 12

(d) 9

Concept Videos :-

#26-Equations-for-Uniform-Acceleration
#27-Equations for Uniform Acceleration 28Calculus Method29
#28-Sign Convention
#29-Solved Examples 16
#31-Solved-Examples-18
#32-Solved Examples 19
#33-Solved Examples 20
#34-Solved-Examples-21
#35 Solved Examples 22
#30-Solved Examples 17

Concept Questions :-

Uniformly accelerated motion

(4)

The problem requires kinematics equations of motion.

Let u and v  the first and final velocities of particle and a and s be the constant acceleration and distance covered by it.

from third equation of motion

Now using first equation of motion,

v=u+ at

or     t=$\frac{v-u}{a}=\frac{20-10}{\left(10/9\right)}=\frac{10×9}{10}=9s$

Difficulty Level:

• 12%
• 17%
• 13%
• 60%