If the lattice parameter for a crystalline structure is 3.6 A0, then the atomic radius in fcc crystal is

(a) 1.81 A0                                  (b) 2.10 A0

(c) 2.92  A0                                (d) 1.27  A0

Atomic radius is the distance between two nearest neighbours. For fcc crystal

Atomic radius = 122×lattice parameter

or               r=a22

or             r=3.622 A0=1.27  A0

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