# NEET Physics Alternating Current Questions Solved

Power dissipated in an L-C-R series circuit connected to an AC source of emf $\epsilon$ is

(a) $\frac{{\epsilon }^{2}R}{\left[{R}^{2}+{\left(L\omega -\frac{1}{C\omega }\right)}^{2}\right]}$

(b) $\frac{{\epsilon }^{2}{\sqrt{{R}^{2}+\left(L\omega -\frac{1}{C\omega }\right)}}^{2}}{R}$

(c) $\frac{{\epsilon }^{2}\left[{R}^{2}+{\left(L\omega -\frac{1}{C\omega }\right)}^{2}\right]}{R}$

(d) $\frac{{\epsilon }^{2}R}{\sqrt{{R}^{2}+{\left(L\omega -\frac{1}{C\omega }\right)}^{2}}}$