NEET Physics Thermodynamics Questions Solved

NEET - 2011

A mass of diatomic gas (γ=1.4) at a pressure of 2 atm is compressed adiabatically so that its temperature rise from 27°C to 927°C. The pressure of the gas is final state is-

(a) 28 atm                                            (b) 68.7 atm

(c) 256 atm                                           (d) 8 atm

Concept Videos :-

#3 | Thermodynamic Processes
#4 | Isobaric Process
#5 | Isochoric & Isothermal Process
#6 | Interconversion of Graphs
#7 | Solved Example: 1
#8 | Solved Example: 2
#9 | Adiabatic Process
#10 | Solved Example: 3
#11 | Graphs in Adiabatic Process: 1
#12 | Graphs in Adiabatic Process: 2

Concept Questions :-

Types of processes

T1=273+27=300 kT2=273+927=1200 k 

Gas equation for adiabatic process

         PVγ=constant 

            PTPγ= constant               (PV=nRT)             P1-γ=CTγP11-γP21-γ=T2γT1γP2P1γ-1=T2T1γ        P2P1=T2T1γγ-10r          P2=P1T2T1γγ-1              P2=212003001.41.4-1              P2=256 atm

Difficulty Level:

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