NEET Physics Nuclei Questions Solved

NEET - 2014


The binding energy per nucleon of 7Li and 4He nuclei are 5.60meV and 7.06meV, respectively.
                                                  3          2

In the nuclear reaction 7Li+1H->4He+4He+Q, the value of energy Q released is
                                  3    1      2      2

(a)19.6MeV

(b)-2.4MeV

(c)8.4MeV

(d)17.3MeV

The binding energy for 1H is around zero and also not given in the question so we can ignore it 
                                  1

Q=2(4x7.06)-7x(5.60)

=(8x7.06)-(7x5.60)

=(56.48-39.2)MeV

=17.28MeV≈17.3MeV

Difficulty Level:

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