The Young's modulus of steel is twice that of brass. Two wires of same length and of same area of cross-section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weight added to the steel and brass wires must be in the ratio of





Concept Videos :-

#2 | Stress
#3 | Strain
#4 | Hooks's Law & Young's Modules
#5 | Bulk Modules & Shear Modules
#6 | Solved Problems: Set 1
#7 | Extension in a Stretched Wire
#8 | Derivation for Energy Stored in a Wire
#12 | Solved Problems: Set 2
#13 | Solved Problems: Set 3

Concept Questions :-

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