NEET Physics Semiconductor Electronics Questions Solved

NEET - 2015

In the given figure, a diode D is connected to an external resistance R = 100 Ω  and an e.m.f of 3.5 V. If the barrier potential developed across the diode is 0.5 V. the current in the circuit will be


(a)30mA

(b)40mA

(c)20mA

(d)35mA

Given, external resistance R=100Ω and emf is 3.5V Potential barrier across the diode is 0.5V


Potential difference on R=3.5V-0.5V=3.0V

Current in circuit I=V/R=3/100=0.03A=30mA

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