If radius of the 23Al nucleus is taken to be RAl then the radius of 125Te nucleus is nearly
                      13                                                                          53

(a)(53/13)1/3 RAl

(b)5/3 RAl

(c)3/5 RAl

(d)(13/53)1/3RAl

Radius of the nucleus is given by

R=RoA1/3=>R∝A1/3

RAl/RTe=(AAl/ATe)1/3=(27/125)1/3=3/5

RTe=5/3RAl

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