NEET Physics Thermodynamics Questions Solved

NEET - 2015

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure.

The change in internal energy of the gas during the transition is

(a) 20 kJ

(b) -20 kJ

(c) 20 J

(d) -12 kJ

For a diatomic gas

CV=5/2R

The change in internal energy of gas in the transition from A to B is

ΔU=nCdT

=n($\frac{5R}{2}$)(TB-TA)

=nR$\frac{5}{2}$ (PBVB/nR - PAVA/nR)

=$\frac{5}{2}$(2x103x6-5x103x4)

=$\frac{5}{2}$x(-8x103)

=-$\frac{4x{10}^{4}}{2}$

=-20 kJ

Difficulty Level:

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