Figure below shows two paths that may be taken by a gas to go from a state A to a state C. In process AB, 400 J of heat is added to the system and in process BC, 100 J of heat is added to the system. The heat absorbed by the system in the process AC will be-


(a) 380 J 
(b) 500 J
(c) 460 J
(d) 300 J

Subtopic:  First Law of Thermodynamics |
 58%
From NCERT
NEET - 2015
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One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure.

The change in internal energy of the gas during the transition is

(1) 20 kJ

(2) -20 kJ

(3) 20 J

(4) -12 kJ

Subtopic:  Molar Specific Heat |
 68%
From NCERT
NEET - 2015
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An ideal gas is compressed to half its initial volume by means of several processes. Which of the following processes results in the maximum work being done on the gas?
1. Adiabatic
2. Isobaric
3. Isochoric
4. Isothermal

Subtopic:  Work Done by a Gas |
 70%
From NCERT
NEET - 2015
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The coefficient of performance of a refrigerator is 5. If the temperature inside freezer is -20°C, the temperature of the surroundings to which it rejects heat is  -

1. 31°C

2. 41°C

3. 11°C

4. 21°C

Subtopic:  Heat Engine & Refrigerator (OLD NCERT) |
 58%
From NCERT
NEET - 2015
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A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is



(1) ρoV

(2) 2ρoVo

(3) ρoVo/2

(4)zero

Subtopic:  Cyclic Process |
 74%
From NCERT
NEET - 2014
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A gas is taken through the cycle A→B→C→A, as shown. What is the net work done by the gas?

(1)2000J

(2)1000J

(3)Zero

(4)-2000J

Subtopic:  Work Done by a Gas |
 70%
From NCERT
NEET - 2013
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During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of CP/CV for the gas is equal to:

1. 4/3 2. 2
3. 5/3 4. 3/2
Subtopic:  Types of Processes | Molar Specific Heat |
 64%
From NCERT
NEET - 2013
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A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is 

(a)2 pV                                     (b)4 pV

(c)12pV                                    (d)pV

Subtopic:  First Law of Thermodynamics |
 76%
From NCERT
NEET - 2012
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One mole of an ideal gas from an initial state A undergoes via two processes. It first undergoes isothermal expansion from volume V to 3V and then its volume is reduced from 3V to V at constant pressure. The correct P-V diagram representing the two processes is -

Subtopic:  Types of Processes |
 75%
From NCERT
NEET - 2012
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An ideal gas goes from state A to state B via three different processes, as indicated in the P-V diagram. If Q1, Q2, Q3 indicates the heat absorbed by the gas along the three processes and U1, U2, U3 indicates the change in internal energy along the three processes respectively, then:

1. \(\mathrm{Q}_1>\mathrm{Q}_2>\mathrm{Q}_3 \) and \(\Delta \mathrm{U}_1=\Delta \mathrm{U}_2=\Delta \mathrm{U}_3\)
2. \(\mathrm{Q}_3>\mathrm{Q}_2>\mathrm{Q}_1\) and \(\Delta \mathrm{U}_1=\Delta \mathrm{U}_2=\Delta \mathrm{U}_3\)
3. \(\mathrm{Q}_1=\mathrm{Q}_2=\mathrm{Q}_3\) and \(\Delta \mathrm{U}_1>\Delta \mathrm{U}_2>\Delta \mathrm{U}_3\)
4. \(\mathrm{Q}_3>\mathrm{Q}_2>\mathrm{Q}_1\) and \(\Delta \mathrm{U}_1>\Delta \mathrm{U}_2>\Delta \mathrm{U}_3\)

Subtopic:  First Law of Thermodynamics |
 80%
From NCERT
NEET - 2012
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