NEET Physics Magnetism and Matter Questions Solved

A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equilibrium state. The energy required to rotate it by ${60}^{\circ }$ is W. Now the torque required to keep the magnet in this new position is

(a) $\frac{W}{\sqrt{3}}$                    (b) $\sqrt{3}W$

(c) $\frac{\sqrt{3}W}{2}$                (d) $\frac{2W}{\sqrt{3}}$

Concept Videos :-

#3 | Magnetic Dipole Moment & Field due to Bar Magnet
#4 | Superposition of Magnetic Field due to Bar Magnet
#5 | Field due to Short Bar Magnet
#6 | Torque Acting on Bar Magnet in Uniform Field
#7 | Work Done in Rotating Dipole in Field & PE
#8 | Oscillations of Bar Magnet in Uniform Field
#9 | Solenoid as Equivalent Bar Magnet

Concept Questions :-

Bar magnet
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