The escape velocity from the earth is about 11 km/second. The escape velocity from a planet having twice the radius and the same mean density as the earth, is

(a)22 km/sec                               (b)11 km/sec

(c)5.5 km/sec                               (d)15.5 km/sec

Concept Questions :-

Escape velocity
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What should be the velocity of earth due to rotation about its own axis so that the weight at equator become 3/5 of initial value. Radius of earth on equator is 6400 km

 (a)  7.4×10-4 rad/sac             

 (b)  6.4×10-4 rad/sac

 (c)  7.8×10-4 rad/sac               

(d)  8.7×10-4 rad/sac 

Concept Questions :-

Acceleration due to gravity
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If g is the acceleration due to gravity at the earth's surface and r is the radius of the earth, the escape velocity for the body to escape out of earth's gravitational field is

(a)gr                                        (b)2gr

(c)g/r                                       (d)r/g

Concept Questions :-

Escape velocity
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The escape velocity of a projectile from the earth is approximately

(a)11.2 m/sec                            (b)112 km/sec

(c)11.2 km/sec                           (d)11200 km/sec

Concept Questions :-

Escape velocity
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The escape velocity of a particle of mass m varies as

(a)m2                                    (b)m

(c)m0                                    (d)m-1

Concept Questions :-

Escape velocity
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Acceleration due to gravity is ‘g’ on the surface of the earth. The value of acceleration due to gravity at a height of 32 km above earth’s surface is (Radius of the earth = 6400 km)

(a) 0.9 g           (b) 0.99g

(c) 0.8 g           (d) 1.01 g

Concept Questions :-

Acceleration due to gravity
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The time period of a simple pendulum on a freely moving artificial satellite is

         (a)   Zero                            (b) 2 sec

         (c)   3 sec                           (d)  Infinite

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For the moon to cease to remain the earth's satellite, its orbital velocity has to increase by a factor of -

(a)2                                                        (b)2

(c)1/2                                                 (d) 4

Concept Questions :-

Orbital velocity
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The height of the point vertically above the earth’s surface, at which acceleration due to gravity becomes 1% of its value at the surface is (Radius of the earth = R)

(a) 8r            (b) 9r

(c) 10r          (d) 20r

Concept Questions :-

Acceleration due to gravity
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The escape velocity of an object from the earth depends upon the mass of the earth (M), its mean density , its radius (R) and the gravitational constant (G). Thus the formula for escape velocity is

(a)v=R8π3Gp                                         (b)v=M8π3GR

(c)v=2GMR                                             (d)v=2GMR2

Concept Questions :-

Escape velocity
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