# NEET Physics Ray Optics and Optical Instruments Questions Solved

A point source of light B is placed at a distance L in front of the centre of a mirror of width d hung vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror at a distance 2L from it as shown. The greatest distance over which he can see the image of the light source in the mirror is

(a) d/2                                     (b) d

(c) 2d                                       (d) 3d

(d) According to the following ray diagram HI=AB=d

and $DS=CD=\frac{d}{2}$

$\because AH=2AD⇒GH=2CD=\frac{2d}{2}=d$

Similarly IJ=d so

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