A wire in the form of a square of side ‘a’ carries a current i. Then the magnetic induction at the centre of the square wire is (Magnetic permeability of free space = ${\mathrm{\mu }}_{0}$)

(a) $\frac{{\mathrm{\mu }}_{0}\mathrm{i}}{2\mathrm{\pi a}}$                   (b)  $\frac{{\mathrm{\mu }}_{0}\mathrm{i}\sqrt{2}}{\mathrm{\pi a}}$

(c)               (d)  $\frac{{\mathrm{\mu }}_{0}\mathrm{i}}{\sqrt{2}\mathrm{\pi a}}$

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