# NEET Physics Alternating Current Questions Solved

An inductor of inductance L and resistor of resistance R are joined in series and connected by a source of frequency ω. Power dissipated in the circuit is

(1) $\frac{\left({R}^{2}+{\omega }^{2}{L}^{2}\right)}{V}$

(2) $\frac{{V}^{2}R}{\left({R}^{2}+{\omega }^{2}{L}^{2}\right)}$

(3) $\frac{V}{\left({R}^{2}+{\omega }^{2}{L}^{2}\right)}$

(4) $\frac{\sqrt{{R}^{2}+{\omega }^{2}{L}^{2}}}{{V}^{2}}$

Explanation is a part of a Paid Course. To view Explanation Please buy the course.

Difficulty Level: