NEET Physics Alternating Current Questions Solved


An inductor of inductance L and resistor of resistance R are joined in series and connected by a source of frequency ω. Power dissipated in the circuit is 

(1) (R2+ω2L2)V

(2) V2R(R2+ω2L2)

(3) V(R2+ω2L2)

(4) R2+ω2L2V2

Explanation is a part of a Paid Course. To view Explanation Please buy the course.

Difficulty Level: