# NEET Physics Alternating Current Questions Solved

In the circuit shown below, the ac source has voltage $V=20\mathrm{cos}\left(\omega t\right)$ volts with ω = 2000 rad/sec. the amplitude of the current will be nearest to

(1) 2A

(2) 3.3 A

(3) $2/\sqrt{5}A$

(4) $\sqrt{5}A$

(1) $R=6+4=10\text{\hspace{0.17em}}\Omega$

${X}_{L}=\omega L=2000×5×{10}^{-3}=10\text{\hspace{0.17em}}\Omega$

${X}_{C}=\frac{1}{\omega C}=\frac{1}{2000×50×{10}^{-6}}=10\text{\hspace{0.17em}}\Omega$

$\therefore \text{\hspace{0.17em}\hspace{0.17em}}Z=\sqrt{{R}^{2}+{\left({X}_{L}-{X}_{C}\right)}^{2}}=10\text{\hspace{0.17em}}\Omega$

Amplitude of current $={i}_{0}=\frac{{V}_{0}}{Z}=\frac{20}{10}=2A$

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