# NEET Physics Alternating Current Questions Solved

The peak value of an alternating e.m.f. E is given by $E={E}_{0}\mathrm{cos}\omega \text{\hspace{0.17em}}t$ is 10 volts and its frequency is 50 Hz. At time $t=\frac{1}{600}sec$, the instantaneous e.m.f. is

(1) 10 V

(2) $5\sqrt{3}\text{\hspace{0.17em}}V$

(3) 5 V

(4) 1 V

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