The potential difference V and the current i flowing through an instrument in an ac circuit of frequency f are given by $V=5\mathrm{cos}\omega \text{\hspace{0.17em}}t$ volts and I = 2 sin ωt amperes (where ω = 2πf). The power dissipated in the instrument is

(1) Zero

(2) 10 W

(3) 5 W

(4) 2.5 W

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