A particle is placed at the origin and a force F = kx is acting on it (where k is positive constant). If U(0) = 0, the graph of U(x) versus x will be (where U is the potential energy function) 

(1)

(2)

(3)

(4)

Concept Questions :-

Elastic potential energy
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A particle moves from a point -2i^+5j^ to 4j^+3k^ when a force of  4i^+3j^ N is applied. How much work has been done by the force?

1. 8 J

2. 11 J 

3. 5 J

4. 2 J

Concept Questions :-

Concept of work
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A body of mass 1 kg begins to move under the action of a time dependent force F=2t i^+3t2 j^ N, where i^ and j^ are unit vectors along X and Y axis, What power will be developed by the force at the time (t) ?

(a) 2t2+4t4W          (b) 2t3+3t4W

(c) 2t3+3t5W          (d) 2t+3t3W

 

 

Concept Questions :-

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Two similar springs P and Q have spring constants KP and KQ, such that KP > KQ. They are stretched, first by the same amount (case a) and then by the same force (case b). The work done by external force, WP and WQ on the springs P and Q in case (a) and case (b) respectively are related as, 

1. WP=WQ ; WP>WQ

2. WP=WQ ; WP=WQ

3. WP>WQ ; WQ>WP

4. WP<WQ ; WQ<WP

Concept Questions :-

Elastic potential energy
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A block of mass 10 kg, moving in the x-direction with a constant speed of 10 ms-1, is subjected to a retarding force F=0.1x J/m during its travel from x=20m to 30m. Its final KE will be :

(a) 475 J
(b) 450 J
(c) 275 J
(d) 250 J

Concept Questions :-

Work done by variable force
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A particle of mass m is driven by a machine that delivers a constant power of k watts. If the particle starts from rest the force on the particle at time t is:
(a) mk2t-1/2

(b) mkt-1/2

(c) 2mkt-1/2

(d) 12mkt-1/2

Concept Questions :-

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Two particles of masses m1,m2 move with initial velocities u1 and u2. On collision, one of the particles get excited to higher level, after absorbing energy ε. If final velocities of particles be v1 and v2, then we must have

(a)m12u1+m22u2-ε=m12v1+m22v2

(b)12m1u12+12m2u2=12m1v12+12m2v22-ε

(c)12m1u12+12m2u22-ε=12m1v12+12m2v22

(d)12m12u12+12m22u22+ε=12m12v12+12m22v22

Concept Questions :-

Work-Energy theorem
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A ball is thrown vertically downwards from a height of 20m with an initial velocity vo . It collides with the ground, loses 50% of it's energy in collision and rebounds to the same height. The initial velocity vo is (Take, g = 10 ms-2)

(a) 14 ms-1

(b) 20ms-1

(c) 28ms-1

(d) 10ms-1

Concept Questions :-

Gravitational Potential energy
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A uniform force of (3i + j) N acts on a particle of mass 2 kg. Hence the particle is displaced from position (2i+k) m to position (4i+3j-k) m. The work done by the force on the particle is-

(a) 9J

(b) 6J

(c) 13J

(d) 15J

Concept Questions :-

Concept of work
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A body of mass m is taken from the earth’s surface to the height equal to twice the radius (R) of the earth. The change is potential energy of body will be

(a)mg2R

(b)2/3mgR

(c)3mgR

(d)1/3mgR


Concept Questions :-

Gravitational Potential energy
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