# NEET Physics Work,Energy and Power Questions Solved

A force $\mathbit{F}=-K\left(y\mathbit{i}+x\mathbit{j}\right)$ (where K is a positive constant) acts on a particle moving in the xy-plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) and then parallel to the y-axis to the point (a, a). The total work done by the force F on the particles is

(1) $-2K{a}^{2}$

(2) $2K{a}^{2}$

(3) $-K{a}^{2}$

(4) $K{a}^{2}$

Concept Videos :-

#3 | Work Done by Variable Force

Concept Questions :-

Work done by variable force
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