A point charge q is placed at a distance a/2 directly above the centre of a square of side a. The electric flux through the square is

(1) $\frac{q}{{\epsilon }_{0}}$

(2) $\frac{q}{\pi {\epsilon }_{0}}$

(3) $\frac{q}{4{\epsilon }_{0}}$

(4) $\frac{q}{6{\epsilon }_{0}}$

Concept Questions :-

Gauss law
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two infinitely long parallel wires having linear charge densities λ1 and λ2 respectively are placed at a distance of R meters. The force per unit length on either wire will be $\left(K=\frac{1}{4\pi {\epsilon }_{0}}\right)$

(1) $K\frac{2{\lambda }_{1}{\lambda }_{2}}{{R}^{2}}$

(2) $K\frac{2{\lambda }_{1}{\lambda }_{2}}{R}$

(3) $K\frac{{\lambda }_{1}{\lambda }_{2}}{{R}^{2}}$

(4) $K\frac{{\lambda }_{1}{\lambda }_{2}}{R}$

Concept Questions :-

Electric field
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The charge on 500 cc of water due to protons will be:

(1) 6.0 × 1027 C

(2) 2.67 × 107 C

(3) 6 × 1023 C

(4) 1.67 × 1023 C

Concept Questions :-

Coulomb's law
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

The electric field in a region is radially outward with magnitude $E=A{\gamma }_{0}$. The charge contained in a sphere of radius ${\gamma }_{0}$ centered at the origin is

(1) $\frac{1}{4\pi {\epsilon }_{0}}A{\gamma }_{0}^{3}$

(2) $4\pi {\epsilon }_{0}A{\gamma }_{0}^{3}$

(3) $\frac{4\pi {\epsilon }_{0}A}{{\gamma }_{0}}$

(4) $\frac{1}{4\pi {\epsilon }_{0}}\frac{A}{{\gamma }_{0}^{3}}$

Concept Questions :-

Gauss law
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Charge q is uniformly distributed over a thin half-ring of radius R. The electric field at the centre of the ring is

(1) $\frac{q}{2{\pi }^{2}{\epsilon }_{0}{R}^{2}}$

(2) $\frac{q}{4{\pi }^{2}{\epsilon }_{0}{R}^{2}}$

(3) $\frac{q}{4\pi {\epsilon }_{0}{R}^{2}}$

(4) $\frac{q}{2\pi {\epsilon }_{0}{R}^{2}}$

Concept Questions :-

Electric field
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

In the given figure two tiny conducting balls of identical mass m and identical charge q hang from non-conducting threads of equal length L. Assume that θ is so small that $\mathrm{tan}\theta \approx \mathrm{sin}\theta$, then for equilibrium x is equal to (1) ${\left(\frac{{q}^{2}L}{2\pi {\epsilon }_{0}mg}\right)}^{\frac{1}{3}}$

(2) ${\left(\frac{q{L}^{2}}{2\pi {\epsilon }_{0}mg}\right)}^{\frac{1}{3}}$

(3) ${\left(\frac{{q}^{2}{L}^{2}}{4\pi {\epsilon }_{0}mg}\right)}^{\frac{1}{3}}$

(4) ${\left(\frac{{q}^{2}L}{4\pi {\epsilon }_{0}mg}\right)}^{\frac{1}{3}}$

Concept Questions :-

Coulomb's law
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Three positive charges of equal value q are placed at the vertices of an equilateral triangle. The resulting lines of force should be sketched as in

(1) (2) (3) (4) Concept Questions :-

Electric field
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

Two equal charges are separated by a distance d. A third charge placed on a perpendicular bisector at x distance will experience maximum coulomb force when

(1) $x=\frac{d}{\sqrt{2}}$

(2) $x=\frac{d}{2}$

(3) $x=\frac{d}{2\sqrt{2}}$

(4) $x=\frac{d}{2\sqrt{3}}$

Concept Questions :-

Coulomb's law
High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

An electric dipole is situated in an electric field of uniform intensity E whose dipole moment is p and moment of inertia is I. If the dipole is displaced slightly from the equilibrium position, then the angular frequency of its oscillations is

(1) ${\left(\frac{pE}{I}\right)}^{1/2}$

(2) ${\left(\frac{pE}{I}\right)}^{3/2}$

(3) ${\left(\frac{I}{pE}\right)}^{1/2}$

(4) ${\left(\frac{p}{IE}\right)}^{1/2}$

High Yielding Test Series + Question Bank - NEET 2020

Difficulty Level:

An infinite number of electric charges each equal to 5 nano-coulomb (magnitude) are placed along x-axis at x = 1 cm, x = 2 cm, x = 4 cm, x = 8 cm ………. and so on. In the setup if the consecutive charges have opposite sign, then the electric field in Newton/Coulomb at x = 0 is $\left(\frac{1}{4\pi {\epsilon }_{0}}=9×{10}^{9}N-{m}^{2}/{c}^{2}\right)$

(1) 12 × 104

(2) 24 × 104

(3) 36 × 104

(4) 48 × 104

Concept Questions :-

Electric field